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Question 583
Genetics → General
Classification
Question
SSBAOptions
Explanation
Four possible bases at each of three positions give 4 × 4 × 4 = 64 possible codons. Removing the three termination codons leaves 61 amino-acid-specifying codons in this model. Since these specify only 20 amino acids, some different codons must specify the same amino acid. This establishes redundancy without implying an equal number of codons for each amino acid, or that every pair of different codons has the same meaning.
Option Validity
A) Triplet possibilities are calculated from the four choices at each of three positions, not from the number of amino acids.
B) The 64 possibilities include three termination codons, which must be removed when counting amino-acid-specifying codons.
C) The model contains 20 amino acids. More coding triplets than amino acids require some repeated amino-acid assignments rather than additional amino acids.
D) The calculation does not establish equal allocation, and exactly three codons for each of 20 amino acids would account for only 60 coding triplets.
Further Reading
Saxena R. Textbook for MRCOG-1: Basic Sciences in Obstetrics and Gynaecology. Jaypee Brothers Medical Publishers; 2016. Chapter 8, Genetics: Deoxyribonucleic Acid, codons and termination sequences. Printed page 254.